$[0/0\mathrm{.}23$ Points$]$

If ${\displaystyle \underset{1}{\overset{7}{}}}f(x)dx=7\mathrm{.}4$ and ${\displaystyle \underset{5}{\overset{7}{}}}f(x)dx=5\mathrm{.}7,$ find ${\displaystyle \underset{1}{\overset{5}{}}}f(x)dx$

$$

Enhanced Feedback

Please try again. Remember, ${\displaystyle \underset{a}{\overset{c}{}}}f(x)dx{\displaystyle \underset{c}{\overset{b}{}}}f(x)dx={\displaystyle \underset{a}{\overset{b}{}}}f(x)dx.$

Need Help? $$

$$