$00$ When a wire that has a large diameter and a length $L$ is connected across the terminals of an automobile battery, the current is

If we cut the wire to half of its original length and connect one piece that has a length $\frac{L}{2}$ across the terminals of the same battery, the current will be

$10$ A $.$

$20$ A$.$

$40$ A$.$

$80$ A$.$

$160$ A$.$