$[0/1$ Points$]$

LARSON$814\mathrm{.}1\mathrm{.}080.$

Consider the following.

${\displaystyle \underset{0}{\overset{1}{}}}{\displaystyle \underset{0}{\overset{x}{}}}f(x,y)dydx={\displaystyle \underset{0}{\overset{1}{}}}{\displaystyle \underset{0}{\overset{y}{}}}f(x,y)dxdy$

Determine whether the statement is true or false. If it is false, which of the following shows it is false. $($Select all that apply.$)$

$f(x,y)=x$

$f(x,y)=y$

$f(x,y)=x+y$

$f(x,y)=x-y$

$f(x,y)=xy$

The statement is true.