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SCALC$9$M $7\mathrm{.}3\mathrm{.}019.$

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Evaluate the integral. $($Use $C$ for the constant of integration.$)$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{\sqrt[\phantom{2}]{x^2-36}}{x^3}dx$

$\frac{(x^2-25{)}^{\frac{3}{2}}}{75x^3}+C$

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Please try again. Whenever $\sqrt[\phantom{2}]{x^2-a^2}$ appears in an integral, you may terms of $.$ Recall the identity: $se{c}^2-1=ta{n}^2.$

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