$[0/2$ Points$]$ I $$ SERPSE$1023.$C$.$OP$\mathrm{.}023.$

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A very thin rod made of glass has a linear charge density of $31\mathrm{.}0n\frac{C}{m}.$ It lies along the line $y=-15\mathrm{.}0cm,$ with one endpoint at $x=0$ and the other at $x=43\mathrm{.}0cm.$ What is the electric field at the origin due to this rod? $($Enter the magnitude in N$/$C and the direction in degrees counterclockwise from the $+x-$axis.$)$

magnitude $$ You may have made a sign mistake when calculating the definite integral for the $x-$component of the electric field. You may have added instead of subtracted when plugging in the lower limit of integration. Note that $\sqrt[\phantom{2}]{y^2}=|y|,$ so when you plug in $x=0,$ the denominator of the expression will be positive. N$/$C

direction $$

Can you use the electric field components and trigonometry to find the angle? Based on the signs of the field components, which quadrant does the field point in$?$ counterclockwise from the $+x-$axis

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