$[0/2$ Points$]$

MY NOTES

HHCALC$68\mathrm{.}4\mathrm{.}017.$

The soot produced by a garbage incinerator spreads out in a circular pattern. The depth, $H(r),$ in millimeters, of the soot deposited each month at a distance $r$ kilometers from the incinerator is given by $H(r)=0\mathrm{.}115e^{-2r}.$

$($a$)$ Write a definite integral giving the total volume of soot deposited within $5$ kilometers of the incinerator each month.

${\displaystyle \underset{0}{\overset{s}{}}}$ dr

$($b$)$ Evaluate the integral you found in part $($a$),$ giving your answer in cubic meters. $($Round your answer to the nearest whole number.$)$

$$ cubic meters