$04\mathrm{.}11\mathrm{.}2024$

On a straight portion of a new road, a rising gradient of $1\mathrm{.}1\%$ was connected to a falling gradient of $1\mathrm{.}5\%$ by a parabolic vertical curve having equal tangent lengths and a length of $200$ m $.$ A point E at a through chainage of $1713\mathrm{.}50$ m on the first gradient was found to have a reduced level of $83\mathrm{.}42$ m AOD and a point $F$ at a through chainage $2107\mathrm{.}60$ m on the second gradient was found to have a reduced level of $82\mathrm{.}80$ m AOD. Calculate; chainage at the intersection, at $P($beginning of curve$)$ and $R($end of the curve$),$ reduced level at the intersection, at $P($beginning of curve$)$ and $R($end of the curve$),$ the highest level on the curve, the chainage of the highest point of the curve, the reduced levels of points on the curve at exact $20$ m multiples of through chainage.