$\mathrm{.}0$ A food stream containing $2\mathrm{.}00mo\frac{l}{m}in$ of butane $(C_4{H}_{10})$ and a feed stream containing $130\mathrm{.}0mo\frac{l}{m}in$ of air are fed into a ceactor. The butane reacts completely according to the given reaction.

$2C_4{H}_{10}+13O_{2}8C{O}_2+10H_{2}O$

Assume that the air is $21\mathrm{.}0$mol$\%O_2$ and $79\mathrm{.}0$mol$\%N_2.$

Set up the cquations neoded to perform a molar balance for each atomic species present. On the left side of each cquation, enter the molar flow rate of the given atomic species into the reactor. On the right side of cach equation, write an expression for the molar flow rate of each atomic species out of the reactor in terms of $q_1,q_2,q_3,$ and $q_4-$

Cin: mol$\frac{C}{m}in=C$ out:

H in: mol$\frac{H}{m}in=H$ out:

$N$ in: mol$\frac{N}{m}in=N$ out:

O in: mol$\frac{O}{m}in=0$ out:

Solve the equations for the flow rates of $q_1((mol)C\frac{O_2}{m}in),q_2((mol)H_2\frac{O}{m}in),q_3((mol)\frac{N_2}{m}in),$ and $q_4((mol)\frac{O_2}{m}in).$

$4=$

molC$\frac{O_2}{m}in$

$q=$

$mol{H}_2\frac{O}{m}in$

$q=$

mol $\frac{N_2}{?}$ min

$44=$

mol $\frac{O_2}{m}in$