Question: 0 Question 22 v Solve for 33. mlz :|:22' If the answer is radical use sqrt(5) to denote J3 (use the correct radicand in the

 0 Question 22 v Solve for 33. mlz :|:22' If theanswer is radical use sqrt(5) to denote J3 (use the correct radicandin the problem!) If the answer is complex use i to denotei. Question Help: E Message instructor D Post to forum Submit Question

0 Question 23 v Solve for m. '/6$+19:.'c+2 Two decimal places works...If the answer is radical use sqrt(5) to denote J3 (use thecorrect radicand in the problem!) If the answer is complex use ito denote 2'. 0 Question 24 v Solve for :c. 163:3 64332

0 Question 22 v Solve for 33. mlz :|:22' If the answer is radical use sqrt(5) to denote J3 (use the correct radicand in the problem!) If the answer is complex use i to denote i. Question Help: E Message instructor D Post to forum Submit Question 0 Question 23 v Solve for m. '/6$+19:.'c+2 Two decimal places works... If the answer is radical use sqrt(5) to denote J3 (use the correct radicand in the problem!) If the answer is complex use i to denote 2'. 0 Question 24 v Solve for :c. 163:3 64332 80a: + 320 = 0 Two decimal places works... If the answer is radical use sqrt(5) to denote J5 (use the correct radicand in the problem!) If the answer is complex use i to denote i. 0 Question 25 v The product of a number and 7 less than the number is 408. Find the numbers. The numbers are C] and Z] Note! The answers are not the factors of 408! ...So the answers are -17 and 24. This makes sense. What the person who wrote this forgot to mention or have students enter is the OTHER factor. If x = -17, then that is the first factor and the other factor is -24, so that (-17)(-24) = 408 If x = 24, then that is the first factor and the other factor is 17, so that (24)(17) = 408

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