00 [2] The Binomial series is given by (1 + :3)\" = Z (a ) :17". It is not hard to show it reduces k k=0 to a polynomial if a = m an integer and otherwise converges absolutely if Iml 1. What if |:1:| = 1'? All is again easy if a: = 1 as it is an alternating series and the remaining part can = (3:) tends to zero as n > 00. What about the case 33 1. 7 I suggest that you consider the ratio \"T":- and attempt to write this as an expansion (1 + n A.+ ..) Then a heavy duty convergence test might apply