Question: 0.0% P CHAN ) = P (N/# ) . PCH ) 0 . 3 5 9 - About 65% of High school student participate in

 0.0% P CHAN ) = P (N/# ) . PCH )0 . 3 5 9 - About 65% of High school studentparticipate in a school athletic team at some level. Roughly 8% of

0.0% P CHAN ) = P (N/# ) . PCH ) 0 . 3 5 9 - About 65% of High school student participate in a school athletic team at some level. Roughly 8% of these athletes go on to play on a college team in the NCAA. What percent of High school student play a sport in high school and go on to play on an NCAA team? 10-(6) Suppose that we know the following information about breast cancer and mammograms: The proportion of women ages 40 or over in this population have breast cancer is 0.005. . . For women who have bread cancer, the probability of a negative mammogram is 0.02. For women who do not have breast cancer, the probability of a positive mammogram is 0.03. If a woman who did a mammogram was found to have breast cancer, what is the probability that she actually has breast cancer? Make a tree diagram. * 2-0.02 0.0049 0- 0 05 0.0049 = 0-141 BC 0- 995 + 0-33 = 0.995 x0. 03= 6. 0299. . bbco- 0+ bhiQ. Q.D BC 1 / 20.97 11 - The Motor Vehicle Department has found that the probability of a person passing the test for a driver's license on the first try is .75. The probability that an individual who fails on the first test will pass on the second try is .80, and the probability that an individual who fails the first and second tests will pass the third time is .70. Find the probability that an individual: a) fails both the first and second tests. 0 .25 b) will require at least two tries to pass the test. 9 / 0.25 X0.2 = 0.05 6/0. 25 x 0. 8 + 0: 05 *0 17 = 12 - Biologists estimate that a randomly selected baby elk has a 30% chance of surviving to adulthood. Assume this estimate is correct. Suppose researchers choose 12 baby elk at random to monitor. a) What is the probability that 5 Elk survive and make it to adulthood? b) What is the probability that less than 5 Elk make it to adulthood? 9 / Bio pdf 6/ Bionomial calf P ( x = 5) = 1 = 12 P(x

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