Question: $$ 0.05=left(frac{sinh phi_{1} 0.5}{sinh phi_{1}} ight) $$CS. SD. 106

 $$ 0.05=\left(\frac{\sinh \phi_{1} 0.5}{\sinh \phi_{1}} ight) $$CS. SD. 106

$$ 0.05=\left(\frac{\sinh \phi_{1} 0.5}{\sinh \phi_{1}} ight) $$CS. SD. 106

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