008 10.0 points Consider the capacitor circuit 8 /F 9 /F ER pe C 3 AF Calculate the equivalent capacitance C'as between points a and b. Answer in units of pF. 009 (part 1 of 2) 10.0 points Consider the system of equivalent capacitors. 2 LF 2 /F 2 LF 2 /F 2 F 2 /F EB Find the equivalent capacitance Cas of the network of capacitors. 1. C = 12 AF 2. C =6 /F 3. C = 4 /F 4.0= : AF 5.0 -2 PF 6.0= AF7. 0 =3 F 8. C= 010 (part 2 of 2) 10.0 points What potential difference must be applied between points a and b so that the charge on each plate of each capacitor will have a magnitude of 6 AC? 1. Vab = 1:51 80 V 2. Va:= 3 V 3. Va:=6V 4. Vab= V 5. Va =4V 6. V. = 18 V 7. Van= 9 V 8. Van = 2 V 011 10.0 points When the switch is in position a, an isolated capacitor of unknown capacitance has been charged to a potential difference of 145 V. When the switch is moved to position b, this charged capacitor is then connected parallel to the uncharged 15.4 aF capacitor. The voltage across the combination becomes 44 V. 15.4 LF CI 145 V Calculate the unknown capacitance. Answer in units of F.012 (part 1 of 3) 10.0 points Consider the two cases shown below. In Case One two identical capacitors are connected to a battery with emf V. In Case Two, a di- electric slab with dielectric constant & fills the gap of capacitor C2. Let C be the resultant capacitance for Case One and O' the resul tant capacitance for Case Two. Case One C1 V Case Two C1 Ca V The ratio of the resultant capacitances is C12 2 1. C12 1 + k 2. Ciz 1 + k C12 2 k 3. K. C12 C12 4. C12 2 5. None of these. 2 k C12 1+ x013 (part 2 of 3) 10.0 points The ratio of potential differences across V2 capacitor Cy for the two cases is 1. None of these. V2 2 k 2. V2 3. V2 4. 2 5. V2 2k 6, - V2 014 (part 3 of 3) 10.0 points The ratio U of total energy stored in the capacitors for the two cases is 1. 2 k 1+k 2. U 2 3. None of theem U 4. 2 5. 2k 6