019 (part 1 of 2) 10.0 points A slingshot consists of a light leather cup attached between two rubber bands. It takes a force of 31 N to stretch the bands 1.3 cm. a) What is the equivalent spring constant of the rubber bands? 1. 2615.38 2. 2538.46 3. 3400 4. 2800 5. 2384.62 6. 2454.55 7. 1933.33 8. 1666.67 9. 2583.33 10. 2727.27 Answer in units of N/m. 020 (part 2 of 2) 10.0 points b) How much force is required to pull the cup of the slingshot 4.2 cm from its equilibrium position? 1. 57.6 2. 66.1333 3. 77.7143 4. 87.8333 5. 81.4286 6. 78.75 7. 50 8. 100.154 9. 69.1538 10. 64.6154 Answer in units of N.10. 25401 01 4 (part 3 of 5) 10.0 points Answer in units of N. Let Af = 400 kg and the coefficient of kinetic friction My = 0.4505. 017 10.0 points Find the magnitude of the acceleration of A box of mass Mon a horizontal tabletop with the system of blocks. ^, and pa nonzero is attached to a spring of 1. 1.64227 negligible mass with force constant &. The 2. 2.006 47 other end of the spring is attached to a wall. 3. 2.20317 If the spring is initially unstretched and the 4. 3.48042 box is moved sideways away from the wall by 5. 2.55716 a distance D, then released, the box remains 6. 3.20959 at rest. 7. 1.28084 D 9. 1.67912 10. 2.70002 Answer in units of m/s . 015 (part 4 of 5) 10.0 points As in Part 3, let A = 400 kg and the coeffi- What must be the magnitude of the static cient of kinetic friction pp - 0.4505. frictional force acting on the box? Find the magnitude of the tension in the cord attached to the 120 kg mass. L. AD - p. Mg 1. 1589.55 2. 1538.2 2. As My 3. 674.201 4. 1238.03 3. AD 5. 1835.13 6. 1131 28 1. None of these 7. 17 40.72 8. 860.504 S. p, Mg - AD 9. 1815.85 10. 1557.02 6. A. Mg+ kD Answer in units of N. 10.0 points 016 (part 5 of 5) 10.0 points An ideal spring obeys Hooke's law: F = -ikr. As in Part 3, let M = 400 kg and the coelli- A mass of m = 0.5 kg hung vertically from clent of kinetic friction pp = 0.4505. this spring stretches the spring 0.2 m. Find the magnitude of the tension in the The acceleration of gravity is 9.8 m/s cord attached to this M = 400 kg mas. Calculate the value of the force constant k 1. 785.684 for the spring 2. 1004.65 1. 147 3. 2245.32 2. 24.5 4. 1502.46 3. 62.3636 5. 855.984 4. 40.1420 6. 2626203 5. 89.0909 7. 797.475 6. 39.2 8. 1980.16 7. 14.7 9. 721.858 8. 70 9. 52.7602 10. 57. 1067 Answer in units of N/m.A crate is sitting in the center of a flatbed truck. As the truck accelerates to the east, 7. Mg the crate moves with it, not sliding on the bed of the truck. 012 (part 1 of 5) 10.0 points In what direction is the friction force ex- Consider the three blocks connected by mass- erted by the bed of the truck on the crate? less inextensible cords over massless friction- less pulleys as shown in the figure below. The 1. To the north coefficient of static friction between the (mid- dle) block and the table top is #, = 0.53 and 2. There is no friction force, because the the system is in equilibrium. crate isn't sliding The acceleration of gravity is 9.8 m/s'. 3. To the west 63 kg 4. To the east As = 0.53 5. To the south 126 kg M ol1 10.0 points Two identical blocks each of mass M are sit- ting one atop the other on a horizontal table Find the maximum value of M for which with negligible friction. A force applied to the system remains in equilibrium. the upper block accelerates the system of two 1. 188.15 blocks across the table. They stay together 2. 185.6 because of the force of static friction. 3. 60.75 F 4. 159.39 M 5. 91.35 a 6. 136.21 7. 154.94 8. 151.38 9. 83.3 10. 60 If the blocks have a horizontal acceleration Answer in units of kg. of magnitude a and the magnitude of hori- zontal force applied to the upper block is F, 013 (part 2 of 5) 10.0 points what is the force of static friction acting on Find the minimum value of M for which the the lower block? system remains in equilibrium. 1. 36 1. 3 F 2. 64.07 Mg 3. 34.76 2. 4. 112 3 5. 65.78 3. Mg 6. 74.98 2 7. 33.12 4. 2 F 8. 92.61 9. 80.83 5. Ma 10. 114.73 Answer in units of kg. 6. FA box of mass m slides without friction on block by a cord rated to withstand a tension a ramp making an angle o with the horizontal. of 132 N. When the elevator starts up, the Another box of the same mass is tied to the cord breaks. first mass by a string, and can fall vertically. The acceleration of gravity is 9.81 m/s. What was the minimum acceleration of the elevator? 1. 4.43242 2. 4.32462 3. 6.00633 T 4. 2.19 5. 6.29526 6. 4.20869 7. 4.79 8. 3.9863 Find the acceleration of the boxes in the 9. 6.85667 simplest possible terms of g and & only. 10. 3.20887 Answer in units of m/s". 1. a = =(1 - sine) 008 10.0 points 2. None of these The weight of an object varies with the 3. a = 2(1 + tan#) 1. speed of the object. 4. a = =(1 + sin #) 2. dimensions of the object. 5. a = g(1 - sine) 3. pull of gravity. 6. a = =(1 -606 9) 1. volume of the object. 006 (part 2 of 2) 10.0 points 009 10.0 points If sind = =, cose = =, and m = 2 kg, find A 6.5 kg bucket of water is raised from a well the tension in the string joining the two boxes by a rope. as they accelerate. The acceleration of gravity is 9.8 m/s'. If the upward acceleration of the bucket is 1. None of these 1.5 m/s', find the force exerted by the rope on the bucket. 2. AN 1. 99.6 2. 32.2 3. 20 N 3. 52.65 4. 12 5. 60.06 4. 18 N 6. 105.84 5. 16 N 7. 88.8 8. 73.45 9. 85.5 6. 12 N 10. 122.01 Answer in units of N. 007 10.0 points A person in an elevator is holding a 11 kg 010 10.0 points\f