Question: (0,2) y = 2 (2,2) X = 0 X = 2 y Path 2 Path 1 y = 0 |(2,0) X The 2 paths has

(0,2) y = 2 (2,2) X = 0 X = 2

(0,2) y = 2 (2,2) X = 0 X = 2 y Path 2 Path 1 y = 0 |(2,0) X The 2 paths has a differential of df = 3ax?ydx + (ax2 + 2by)dy. It can be shown that going from origin to pt (2.2) is path independent. True or False? Justify your answer. True O False

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