-.05pt'> Chemistry: 1. An atom of fluorine contains nine electrons. How many of these electrons are in orbitals? A) 2 B) 6 C) 8 D) 4 E) none

2.The equilibrium constant for the chemical equation

is at . Calculate the value of the for the reaction at .

Kc=

Sol28:

1. E) none. An atom of fluorine has the electron configuration 1s2 2s2 2p5. All 7 electrons in the 2p sublevel are in p orbitals, not s orbitals.
2. K_c = K_D(RT)^?n, where ?n is the difference in moles of gas between products and reactants. In this case, ?n = (2-1-3) = -2. R = 0.082 L atm/mol K, and T = 269 + 273 = 542 K. Plugging in the values: K_c = 0.00166(0.082)(542)^(-2) = 5.24 x 10^(-5) L/mol.