$100$GPa.If point $C$ moves $=0\mathrm{.}15mm$ to the left, what is the applied force?

Learning Goal:

To solve for forces in statically indeterminate bars with axial loads.

When the number of reaction forces is greater than the number of equilibrium equations, the

system is statically indeterminate. Solving for the reactions requires some additional

equations. These additional equations come from considering compatibility relationships $($i$.$e$.$

continuity of displacements and relationships between displacements and loads$).$

For an axially loaded member, the compatibility relationship for the deflections can be written

by setting the total relative axial displacement between the ends of the member to a known

value. The load$-$displacement relationship $={\displaystyle \underset{?}{\overset{?}{}}}\frac{NL}{AE}$ gives another equation for the

deflections. Once the internal normal force of each segment is written in terms of the end

reactions and applied loads, there is enough information to solve for the reactions.

Express your answer with appropriate units to three significant figures.

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Correct

Correct answer is shown. Your answer $106\mathrm{.}777$ kN was either rounded differently or used a different number of significant figures than required for this part.

Part B $-$ Reaction with a known load

reaction act to the right. The total length is still $6m.$

Express your answer with appropriate units to three significant figures.

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$F_A=$

Incorrect; Try Again; $4$ attempts remaining

Part C $-$ Load point for equal forces

Consider the structure from Part B $($Figure $2).$ What value of $x$ will lead to equal reaction forces at A and $B?$

Express your answer in feet to three significant figures.

$1$ View Available Hint$($s$)$

Figure

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