$10-$

Find the general solution to the following differential equation:

$x^2{y}^{\text{'}\text{'}}+x{y}^{\text{'}}+y=\frac{1}{cos(lnx)}$

a

$$

$.y=C_{1}cos(lnx)+C_{2}sin(lnx)+(lnx{)}^{2}cos(lnx)+lnxsin(lnx)$

d $y=C_{1}cos(lnx)+C_{2}sin(lnx)+ln(sin(lnx))cos(lnx)+(lnx{)}^{2}sin(lnx)y=C_{1}cos(lnx)+C_{2}sin(lnx)+ln(cos(lnx))cos(lnx)+lnxsin(lnx)$

$$

$y=C_{1}cos(lnx)+C_{2}sin(lnx)+lnxcos(lnx)+lnxsin(lnx)$

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