Question: ( 1 0 points ) In class we cover the proof of Theorem 5 . 3 that the language R E G T M :

(10 points) In class we cover the proof of Theorem 5.3 that the language
REGTM:={(:M:)|MisaTM and L(M)is regular }
is undecidable. We showed that REGTM is not co-recognizable.
(a)(2 points) These two arguments (not decidable and not co-recognizable) can be
captured by a single mapping reduction. What is the mapping reduction? (Give a
description of the function f.)
(b)(6 points) Give a different mapping reduction from ATM to show that REGTM is
not recognizable.
(c)(1 point) Describe these two mapping reductions using the ?m notation.
(d)(1 point) What is your final classification of REGTM in the Chomsky hierarchy?
(Please please DON'T USE AI Thank you! I promise I will give you thumbs up if you answer this correctly)
 (10 points) In class we cover the proof of Theorem 5.3

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