Question: [ 1 0 points ] We can easily see that x 1 = x 2 = x 3 = 1 is a feasible point for

[10 points] We can easily see that x1=x2=x3=1 is a feasible point for the following linear
program:
Maximize u=4x1+2x2+3x3
Subject to:
2x1+3x2+x312
x1+4x2+2x310
3x1+x2+x310
x1,x2,x30
a) Write this LP with slack variables. What are the values of the slack variables at the point
x1=x2=x3=1? What is the value of the objective function at this point?
b) Without solving the problem, identify which variables are basic and which are non-basic
at this point.
c) What is the dual of this LP? Write it in minimum form with all surplus variables.
d) Note that each constraint in the LP has a unique variable, and that there is a dual
variable that corresponds to that constraint. These are called complimentary variables.
List all the pairs of complimentary variables in your primal and dual LP.
e) Find any feasible point for the dual. What are the values of all the dual variables
(including slack variables) at this point? What is the value of the dual objective function
at this point?
f) Multiply together the values of all the pairs of complimentary variables (giving 6
products) then add them together. What do you get? Compare this to the difference
between the value of the dual objective function you calculated in (e) and the value of
the primal objective function from (a). What do you notice?
g) Solve both the primal and the dual LPs (you can use a solver). What are the values of all
the variables at the optimum? What do you notice about the product of each of the
pairs of complimentary variables? This is a property of primal/dual linear programs
called Tucker Duality.
 [10 points] We can easily see that x1=x2=x3=1 is a feasible

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