Question: ( 1 0 pt ) Consider the demand paging, the normal memory access time = 2 0 0 nanoseconds, and the average page - fault

(10pt) Consider the demand paging, the normal memory access time =200 nanoseconds, and the average
page-fault service time =4 milliseconds. Given page fault rate P, effective access time EAT =(1-p)*
memory access time +p*page-fault service time.
(5pt)1) If one access out of 3,000 causes a page fault, calculate the effective access time.
(5pt)2) If we want the performance degradation 80%, In how many page accesses do we allow one page
fault?
( 1 0 pt ) Consider the demand paging, the normal

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