$10xx2\sqrt[\phantom{2}]{16}-x2-y2dydx.$ Sketch the region $of$ integration. Change the Cartesian integral into $an$ equivalent polar integral.

$(3)$ Consider

${\displaystyle \underset{0}{\overset{1}{}}}{\displaystyle \underset{x^2}{\overset{x}{}}}\sqrt[\phantom{2}]{16-x^2-y^2}dydx$

Sketch the region $of$ integration. Change the Cartesian integral into $an$ equivalent polar integral.