$1$

$10.$ The data should be linear. Add a line of best fit through the data. Put a title on the graph.

$11.$ Calculate the slope of the line. Choose two points on the line that are on the corners of the grid, and far apart. Do not use data points to calculate the slope. Indicate the two points used to calculate the slope on the graph. Show the calculation of the slope below. Note that the $ln$ of $P$ has no units, but $\frac{1}{T}$ has the units of $K^{-1}.$ As a result, the slope will have units.

Slope $=$

$12.$ The slope of the line has physical significance. The slope is used to calculate the enthalpy of vaporization, $H_{\text{v}\text{a}\text{p}}.$ The enthalpy of vaporization is the energy needed to vaporize a mole of a substance at its normal boiling point.

Slope $=-\frac{H_{\text{v}\text{a}\text{p}}}{R}$

Where $R=8\mathrm{.}314\frac{J}{m}ol-K$

Show the calculation of the enthalpy of vaporization below. Pay attention to the sign and units.

Result: $H_{\text{v}\text{a}\text{p}}=$

$13.$ Look up the value of the enthalpy of vaporization of water in your textbook or online. Calculate the $\%$ error using the value from your graph and the accepted value. Show your calculation below. Be sure to look at the units, and to any appropriate conversions. Your value will be calculated in units of joules $(J)$ while many times the enthalpy of vaporization may be given in kilojoules $(kJ)$

$\%$ error $=\frac{|H_{\text{v}\text{a}\text{p}}\text{f}\text{r}\text{o}\text{m}\text{g}\text{r}\text{a}\text{p}\text{h}-\text{a}\text{c}\text{t}\text{u}\text{a}\text{l}{H}_{\text{v}\text{a}\text{p}}|}{\text{a}\text{c}\text{t}\text{u}\text{a}\text{l}{H}_{\text{v}\text{a}\text{p}}}100\%$

Result: $\%$ error $=$