Question: 1 1 . 1 0 LAB: Quadratic formula Implement the quadratic _ formula ( ) function. The function takes 3 arguments, a , b ,

11.10 LAB: Quadratic formula Implement the quadratic_formula() function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic formula: See Image The quadratic_formula() function returns the tuple (x1, x2). Ex: When a =1, b =-5, and c =6, quadratic_formula() returns (3,2). Code provided in main.py reads a single input line containing values for a, b, and c, separated by spaces. Each input is converted to a float and passed to the quadratic_formula() function. Ex: If the input is: 2-3-77 the output is: Solutions to 2x^2+-3x +-77=0 x1=7 x2=-5.50 SEE UPLOADED IMAGE for better view 11.10 LAB: Quadratic formula Implement the quadratic_formula() function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic formula:
[ x_1=-b+(b^2-4 a c)/2 a; x_2=-b-(b^2-4 a c)/2 a ]
The quadratic_formula0 function returns the tuple (x 1, x 2). Ex: When a=1, b=-5, and c=6, quadratic_formula() returns (3,2). Code provided in main.py reads a single input line containing values for a, b, and c, separated by spaces. Each input is converted to a float and passed to the quadratic_formula( function. Ex: If the input is:
[2-3-77]
the output is:
[ Solutions to 2 x^2+-3 x+-77=0; x 1=7; x 2=-5.50]
main.py 1 # Produces the roots of the given quadratic equation. # Does not consider overflow. Does not solve for imaginary roots. def quadratic_formula (a, b, c) : # Check if the solution is imaginary if b^**2-4^* a^* c<0 : return None, None x 1=(-b+. math .sqrt(b^**2-4^* a^* c))/2.0/ a x 2=(-b-. math. sqrt .(b^**2-4^* a^* c))/2.0/ a return \times 1,\times 2

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