1 2 1 4 2 1 0 Response b. Step1: Find crash cost per unit of time and max. crash time for each activity. Feedback: ID Slope Maximum Critical crash A 20 B 40 30 D 25 y E 30 F 30 y G 0 Step 2: Crash activity A by 1 week Step 3: crash activity D by 1 weeks. Crashing activity D more than one unit of time will not reduce the project completion time since new CP is ACFG. Similarly, crashing C will not shorten the project. Crashing them simultaneously will cost $56/day. However, crashing F will cost $30/day. Step 4: Crash activity F by 1 week Total cost is 470+20+25+30-$525,000 c. Planned values and budgeted cost is shown below Weeks CPV CBC ID 5 33.3% 33.3% 33.3% 100% 50 16.6 16.6 20% 16 10 20% D 9.1 9.1 18 2% 9.1 CAC 51+30+12+10= $103K CBC = 50+16+12+9.1=$87.1K CPI = CEV/CAC=87.5/103 -84.5% CC = TBC / CPI 450/0.845=$532.1 2 3 4 B 10 12 1 2 1 4 2 1 0 Response b. Step1: Find crash cost per unit of time and max. crash time for each activity. Feedback: ID Slope Maximum Critical crash A 20 B 40 30 D 25 y E 30 F 30 y G 0 Step 2: Crash activity A by 1 week Step 3: crash activity D by 1 weeks. Crashing activity D more than one unit of time will not reduce the project completion time since new CP is ACFG. Similarly, crashing C will not shorten the project. Crashing them simultaneously will cost $56/day. However, crashing F will cost $30/day. Step 4: Crash activity F by 1 week Total cost is 470+20+25+30-$525,000 c. Planned values and budgeted cost is shown below Weeks CPV CBC ID 5 33.3% 33.3% 33.3% 100% 50 16.6 16.6 20% 16 10 20% D 9.1 9.1 18 2% 9.1 CAC 51+30+12+10= $103K CBC = 50+16+12+9.1=$87.1K CPI = CEV/CAC=87.5/103 -84.5% CC = TBC / CPI 450/0.845=$532.1 2 3 4 B 10 12