Question: 1. 2 3 7 The vectors , = and V, = span a subspace V of the indicated Euclidean space. Find a basis for the
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2 3 7 The vectors , = and V, = span a subspace V of the indicated Euclidean space. Find a basis for the orthogonal complement V- of V. 3 9 6 . . . Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. O A. A basis for the orthogonal complement V is (Use a comma to separate vectors as needed.) O B. There is no basis for the orthogonal complement v.A homogeneous second-order linear differential equation, two functions y1 and y2, and a pair of initial conditions are given. First verify that y1 and Y2 are solutions of the differential equation. Then nd a particular solution of the form y = c1y1 + c2y2 that satisfies the given initial conditions. Primes denote derivatives with respect to x. y\"+2y'+y=0;y1=e'x,y2 =xe_x; y(0)=5, y'(0)= -2 Why is the function y1 = e' X a solution to the differential equation? Select the correct choice below and fill in the answer box to complete your choice. 9-:5' A- The function y1 = e' x is a solution because when the function and its indefinite integral, , are substituted into the equation, the result is a true statement. U B- The function y1 = e x is a solution because when the function, its rst derivative y1 ' = and its second derivative, y1 \" = , are substituted into the equation, the result is a true statement. Why is the function y2 = xe'x a solution to the differential equation? Select the correct choice below and fill in the answer box to complete your choice. '3' A- The function y2 = xe_x is a solution because when the function, its derivative, y2' = , and its second derivative, y2\" = , are substituted into the equation, the result is a true statement. '3' B- The function y2 = xe_x is a solution because when the function and its indefinite integral, , are substituted into the equation, the result is a true statement. The particular solution of the form y = c1y1 + czy2 that satisfies the initial conditions y(0) = 5 and y'(0) = - 2 is y =
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