$(12\text{'})$ Problem $1.$

A single$-$phase transformer has a turns ratio of $1000/200$ the following parameters: $R_1=0\mathrm{.}3,R_2=12m,R_0=1000,x_{l1}=0\mathrm{.}2,x_{l2}=0\mathrm{.}008,x_0=2000.$ The input voltage is $480$ V $($rms voltage$).$ The secondary winding is powering a load and the load impedance is $\frac{?}{\text{b}\text{a}\text{r}}(Z{)}_2=0\mathrm{.}4+j0\mathrm{.}1$ Use the following equivalent circuit for calculation.

$(2\text{'})$ Explain the physical meanings of the components in the above equivalent circuit.

$(2\text{'})$ Secondary winding current phasor $\frac{?}{\text{b}\text{a}\text{r}}(I{)}_2(no\frac{t}{b}ar(I{)}_2^{\text{'}})$

$1/4$

$(1\text{'})$ Load voltage phasor $\frac{?}{\text{b}\text{a}\text{r}}(V{)}_2(no\frac{t}{b}ar(V{)}_2^{\text{'}})$

$(2\text{'})$ Primary winding current phasor $\frac{?}{\text{b}\text{a}\text{r}}(I{)}_1$

$(1\text{'})$ Copper losses on primary and secondary windings

$(1\text{'})$ Core loss

$(3\text{'})$ Transformer efficiency