Question: 1 2 ( x + 6 y ) d x = [ 1 2 x 2 + ( ) x y ] | 1 2

12(x+6y)dx=[12x2+()xy]|12|
=32+()y
1 2 ( x + 6 y ) d x = [ 1 2 x 2 + ( ) x y ] | 1 2

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