Question: 1: ????2????4 + 0.5 ????2 ????2????4???? ????1 = 400 ????????????/???? ????2: ????2????4 + 3 ????2 2 ????????2 + 2 ????2???? ????2 = 80 ????????????/???? The
1: ????2????4 + 0.5 ????2 ????2????4???? ????1 = 400 ????????????/???? ????2: ????2????4 + 3 ????2 2 ????????2 + 2 ????2???? ????2 = 80 ????????????/???? The oxygen feed contains inert (which does not react) at 5000 ppm (on a molar basis), which must be purged. The flow rate of the purge (stream 8) is set to control the reactor feed (stream 3) at 10 mol% inert. a) What is the limiting reactant? Explain. b) Determine the molar flow rate of inert in the reactor feed (stream 3) and molar flow rates of all reactor components in the reactor effluent (stream 4) and enter them into the stream table. c) What is the fractional conversion of oxygen in the reactor? d) What is the selectivity of the reactor? e) Use all the information provided to complete the stream table. Provide the completed stream table with your assignment. f) Demonstrate an overall carbon balance for the process (i.e., an elemental balance on carbon for the overall process). If it does not balance, explain why. g) How much ethylene (which is an expensive feed) is lost in the purge, expressed as a fraction of the fresh feed of ethylene? How much of ethylene is lost due to reaction 2, expressed as a fraction of the fresh ethylene feed? If you were trying to improve the overall process yield of ethylene oxide, where would you focus your efforts? h) What is the yield in the reactor of ethylene to ethylene oxide? Also, what is the overall process yield of ethylene to ethylene oxide and of oxygen to ethylene oxide? Explain why there are differences in
Table 1: Stream table corresponding to the flowsheet of Figure 1. (Note that only molar flo rates need to be provided. Mole fractions can be calculated from these molar flow rates Component | MW 1 2 3 4 5 6 7 8 9 C2H, 28 0 4800 0 0Step by Step Solution
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