$=\frac{1}{3}+\frac{1}{2}$

$=\frac{5}{6}$

The area of the region is $\frac{5}{6}$ units ${?}^2.$

$4=\frac{x-a}{2}$

$4^{-\frac{1}{4}}$

$\sqrt[\phantom{2}]{4+12}$

$\frac{94}{2}$

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Question

Find the area of the region that is bounded between the curve

$f(x)=(x+9{)}^2$

and the line

$g(x)=-x-7$

and bounded below by the $x-$axis. Enter your answer as an exact answer.

Provide your answer below:

$A=($