$13$:$25$

$-=$ Chegg

Step $1$ of $4$

The reaction of methylamine $($A$)$ to dimethylamine

$(B)$ is as follows:

$2C{H}_{3}N{H}_{2}longleftrightarro{w}_{\text{c}\text{a}\text{t}}(C{H}_3{)}_{2}NH+N{H}_3$

$2Alongleftrightarro{w}_{\text{c}\text{a}\text{t}}B+C$

The above reaction takes place in a packed bed reactor consisting of a silica$-$alumina catalyst as shown in the following figure.

Silica$-$alumina catalvst

Figure. $1$ Packed bed reactor with silica$-$alumina catalyst The molar feed rate $(F_{A0})$ into a PBR is $23\mathrm{.}6mo\frac{l}{s}$ and the entering pressure $(P_0)$ is $18$ atm. Assume that there is no pressure drop or temperature change $($isothermal$)$ in the reactor.

The reaction rate follows an elementary rate law in terms of partial pressure.

Provided the forward reaction rate constant $(k_1)$ is $4\mathrm{.}25{10}^{-6}\frac{\text{m}\text{o}\text{l}}{at{m}^2*\text{g}\text{c}\text{a}\text{t}\text{a}\text{l}\text{y}\text{s}\text{t}*s}$ and equilibrium constant $(k_e)$ is $2\mathrm{.}5.$

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