$13\mathrm{.}7$ Problems

Calculate SSD for $V=50kmph$ for $($a$)$ two$-$way traffic in a two lane road $($b$)$ two$-$way traffic in single lane road. $($Hint: $f=0\mathrm{.}37,t=2\mathrm{.}5)[$Ans: $($a$)61\mathrm{.}4m($b$)122\mathrm{.}8m.$

Given: $V=50k\frac{m}{h}r=13\mathrm{.}9\frac{m}{s}f=0\mathrm{.}37t=2\mathrm{.}5sec$ stopping distance$=$lag distance $+$ braking distance

$SD=vt+\frac{v^2}{2}gf$

Stopping Distance $=61\mathrm{.}4m$

Stopping sight distance when there are two lanes $=$ stopping distance $=61\mathrm{.}4m.$

Stopping sight distance for a two way traffic for a single lane stopping distance