Question: (1) (3 points) Substituting appropriate values for x and y into the Binomial Theorem show that n n (a) (7) k=0 n k (b)

(1) (3 points) Substituting appropriate values for x and y into the Binomial Theorem show that n n (a) (7) k=0 n k (b) (-1) = 2n == n -*(*) k=0 n k = = 0 (c)(2)(a 1) = a k=0 k -

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