$(14$ p$($s$)$ Two, point charges are lying on the $x$ axis as in the figure: $q_1=+12\mathrm{.}00C$ and $q_2=-12\mathrm{.}00C.$ They are equidistant from the point $P,$ which lies on the $x$ axis. $)=(\frac{\text{I}}{x}$I $0C$

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$q,$