Question: 1 , 5 0 0 for machine 2 ; and 1 , 6 0 0 for machine 3 . The processing times are as follows:

1,500 for machine 2 ; and 1,600 for machine 3. The processing times are as follows:
Processing Time (hr)
\table[[Component,Machine 1,Machine 2,Machine 3],[A,0.25,0.10,0.05],[B,0.20,0.15,0.10],[C,0.10,0.05,0.15]]
1 and 110,000 ounces of raw material 2 are available.
Requirements (oz/unit)
\table[[Requirements (oz/unit)],[Component,Raw Materlal 1,Raw Material 2,Selling Price ($/unit)],[A,32,12,40.00],[B,26,16,28.00],[C,19,9,24.00]]
constraints for the problem.
Objective function: Maximize Z=29.40A+17.20B+17.05C.(Enter your responses rounded to two decimal places.)
Constraints (enter your responses rounded to two decimal places):
Machine 1(C1) :
Machine 2(C2) :
Machine 3(C3) :
Material 1(C4) :
\table[[0.25A+0.20B+0.10C,1600],[0.10A+0.15B+0.05C,1500],[0.05A+0.10B+0.15C,1600]]
Material 2(C5) :
32A+26B+19C204000
Minimum for product (C6) :
12A+16B+9C110000
Nonnegativity:
B1,200
A0,B0,C0
b. A linear programming software shows the optimal solution as: B=1,200 and C=0. What is the optimal value for A?
 1,500 for machine 2 ; and 1,600 for machine 3. The

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related General Management Questions!