Question: ( 1 . 5 ) 0 3 2 1 ( 4 x 2 + 9 ) 3 2 d x , Using the substitution x

(1.5)0321(4x2+9)32dx, Using the substitution x=32tanu
( 1 . 5 ) 0 3 2 1 ( 4 x 2 + 9 ) 3 2 d x , Using

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