$[15]3)x^{2}y=1.$ Find $\frac{d}{dx}[y(x)]$ only implicitly.

implicit $y^{\text{'}}=y^{\text{'}}=-\frac{y}{x}=-\frac{1}{2}=\frac{-1}{x}$

Explicit: $y(x{)}^2=\frac{1}{2}=>y^{\text{'}}(x)=-\frac{1}{x^2}$

$[15]4)f(x)=x^2$

$[5]$ a$)$ what is the differential of at $x?($hint: df $(h)=?)$

$df(h)=x^2,f(x)=x^2,$dfi$(h)$

$f^{\text{'}}(x)n=-x^2*h$

$[5]$ b$)$ Find the actual change in from $x=1$ to $?)$

$3$

$f_f(h)=df(x)(h)=>d{f}_1(-1\mathrm{.}05+-(1))=\frac{1}{(14{)}^2}$

$[5]$ c$)$ Find $d{f}_x(h)$ from $x=1$ to $x=1\mathrm{.}05.$