$(15$ points$)$ Determine the net area for the $L5\frac{3\mathrm{.}1}{2}\frac{1}{2}($ASTM A$36)$ tension member shown in the figure

below. The angle has one line of $\frac{3}{4}$ inch diameter bolts in each leg. The bolts are $3$ inches on center in each

line and are staggered $\frac{1\mathrm{.}1}{2}$ inches with respect to each other. Make sure you include units for all final answers.

$L53\mathrm{.}5\frac{1}{2}$

$A=4\mathrm{.}79$