Question: 1 6 . 9 8 A ball suspended from a string that goes through a hole in the ceiling at O moves with velocity v

16.98 A ball suspended from a string that goes through a hole in the ceiling at O moves with velocity vA in a horizontal circular path of radius rA. The string is then drawn through the hole until the ball moves with velocity vB in a horizontal circular path of radius rB. Use the principle of angular impulse and momentum to show that rAvA=rBvB.
Strategy: Let e be a unit vector that is perpendicular to the ceiling. Although this is not a central-force problem-the ball's weight does not point toward O-you can show that e*(rF)=0, so that e*HO is conserved.
Problem 16.98

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