$16-P+$NHO$3+H_{5}OH3PO4+NO$

about the reaction

I. When balanced with the smallest integers, the coefficient of $H_{0}O$ is $2.$

II$.$ HNO$3$ is oxidizing

III. $P$ is the reducer.

Which of your judgments is correct?

A$)$ Only I

B$)$ Only II

C$)$ I and I

D$)$ II and III

E$)$ I, II and III