Question: 1- 80% confidence interval: C180% = 84.74 +- 1.28 * (4.32/7.07) = 84.74 +- 0.78 = (85.52, 83.96) Here, margin of error is 20%

1- 80% confidence interval: C180% = 84.74 +- 1.28 * (4.32/7.07)

1- 80% confidence interval: C180% = 84.74 +- 1.28 * (4.32/7.07) = 84.74 +- 0.78 = (85.52, 83.96) Here, margin of error is 20%

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!

Q:

duction In this analysis we first examined the general attitude of shoppers toward each shopping area. We found that the point estimate of the population mean attitude toward the Springdale shopping...

Q:

Complete the following Nolan and Heinzen end-of-chapter exercises for Chapter 8: 8.15, 8.22, 8.26, and 8.40. If applicable, remember to show work in your homework document to receive partial credit....

Q:

You will do a Course Project in this course that will span two weeks. The project is broken into two parts. You will complete Part I in Week 6 and Part II in Week 7. In Week 6, Confidence Intervals...

Q:

Course Project, Part I Directions: Please review the two articles listed below. Confidence Intervals, Pt. 1:...

Q:

Directions: 1. Use the table above to find the 80%, 95%, and 99% confidence interval. 2. Choose another confidence level (besides 80%, 95% or 99%) for another confidence interval..3.Provide a...

Q:

Directions: Use the table above to create an 80%, 95%, and 99% confidence interval. Choose another confidence level (besides 80%, 95% or 99%) to create another confidence interval. Provide a sentence...

Q:

Sample Data 49 25 20 7 8 36 6 2 44 7 8 34 42 42 35 25 43 39 47 51 21 27 43 10 18 13 34 12 11 5 13 27 9 49 24 29 32 10 18 21 2 12 7 7 44 53 12 11 Directions: Use the table above to create an 80%, 95%,...

Q:

lag question: Question 1 The mean of patient satisfaction scores from a patient satisfaction survey with samples n = 36 is 49.5. Score standard deviation in population=6is assumed to be known. Given...

Q:

lag question: Question 1 The mean of patient satisfaction scores from a patient satisfaction survey with samples n = 36 is 49.5. Score standard deviation in population=6is assumed to be known. Given...

Q:

MS1023 Business Statistics with Computer Applications MS1023 Business Statistics w/Comp Apps I Homework #3 - Use Red Par Score Form Chp. 7: Questions 1-50 1. Kristen Ashford purchased the subscribers...

Q:

Ever Financial paid $560,000 for a 20% investment in the common stock of Laker, Inc. For the first year, Laker reported net income of $220,000 and at year-end declared and paid cash dividends of...

Q:

Discuss the factors to be considered when analyzing the receiver of a message to ensure your intended message is received.

Q:

Which of the following is most likely to occur upon termination of a project? Question 1 4 options: Sunk cost. Opportunity cost. Working capital recapture. Operating cost. Depreciation cost.

Q:

13A Exercises ... A Saved Help Save & Exit Submit Check my work Exercise 13A-4 (Algo) Target Costing (LO13-11) Shimada Products Corporation of Japan plans to introduce a new electronic component to...