(1) A 15-kva single-phase transformer designed for [(2,400)/(240)] volts. An open-circuit test on the 240-V winding...

 

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(1) A 15-kva single-phase transformer designed for [(2,400)/(240)] volts. An open-circuit test on the 240-V winding of the transformer in the figure yielded the following data, corrected for instrument losses: Volts Amperes Watts 580 240 16.75 Calculate the parameters of the core Rc and Xm. (2) The following data were obtained in a short-circuit test of the transformer in the figure, with its low-voltage winding short-circuited. 7 CC (₂) 0.216+/0.443 www Calculate (a) the equivalent primary impedance, (b) the equivalent primary resistance, (c) the equivalent primary reactance. Rc Volts Amperes Watts 63.0 62.5 1660 Thu 0.0021+/0.00454 V₁ - 240 V Xm Equivalent circuit (3) Calculate the approximate value of the primary supply voltage at full load, S= 15 KVA 80 percent power factor (lagging), when the secondary voltage is 240 volts, (1) A 15-kva single-phase transformer designed for [(2,400)/(240)] volts. An open-circuit test on the 240-V winding of the transformer in the figure yielded the following data, corrected for instrument losses: Volts Amperes Watts 580 240 16.75 Calculate the parameters of the core Rc and Xm. (2) The following data were obtained in a short-circuit test of the transformer in the figure, with its low-voltage winding short-circuited. 7 CC (₂) 0.216+/0.443 www Calculate (a) the equivalent primary impedance, (b) the equivalent primary resistance, (c) the equivalent primary reactance. Rc Volts Amperes Watts 63.0 62.5 1660 Thu 0.0021+/0.00454 V₁ - 240 V Xm Equivalent circuit (3) Calculate the approximate value of the primary supply voltage at full load, S= 15 KVA 80 percent power factor (lagging), when the secondary voltage is 240 volts,

Answer rating: 100% (QA)

14 TOYS Fagemege V 240V I 16 45 A W 580 W W v cas Cos 0 W V I 580 Rc Xm V ... View the full answer