$1.$ A seesaw is made from a $5-$meter$-$long $56\mathrm{.}0$ kg rod of uniform mass distribution which rests on a fulcrum located in the center of the rod.$$ If a $42$ kg child sits so that his center of mass is located $2\mathrm{.}20$m away from the pivot point,

A$.$ What is the moment of inertia of the seesaw and child? $($treat the child as a point mass to find the total inertia of the seesaw$-$child system.$)$

B$.$ How much torque would be needed to cause an angular acceleration of $0\mathrm{.}15$ rad$/$s$2?$

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