1. A student was asked to find a 99% confidence interval for the proportion of students who take notes using data from a random sample of size n = 80. Which of the following is a correct interpretation of the interval 0.13 < p < 0.35?

Check all that are correct.

• With 99% confidence, the proportion of all students who take notes is between 0.13 and 0.35.
• With 99% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.13 and 0.35.
• There is a 99% chance that the proportion of the population is between 0.13 and 0.35.
• There is a 99% chance that the proportion of notetakers in a sample of 80 students will be between 0.13 and 0.35.
• The proprtion of all students who take notes is between 0.13 and 0.35, 99% of the time.

2. Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 383 with 32.1% successes at a confidence level of 99.8%.

3. Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 311 with 171 successes at a confidence level of 95%. 4. Out of 600 people sampled, 540 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. -to three places ? < p < ?

5. Express the confidence interval (79.5%,96.9%)(79.5%,96.9%) in the form of pMEp^ME.