$1$a$.$ Two airplanes leave an airport at the same time. The velocity of the first airplane is $710$ m$/$h at a heading of $49\mathrm{.}5$ degrees. The velocity of the second is $580$ m$/$h at a heading of $154$ degrees. How far apart are they after $3\mathrm{.}3$ h$?$ Answer in units of m$.1$b$.$ Consider $2$ vectors A &B and their resultant A$+$B$.$ The magnitudes of the vectors A and B are respectively $17\mathrm{.}3$ and $8\mathrm{.}2$ and they act at $99$ degrees to each other. Find the magnitude of the resultant vector A$+$B$.1$c$.$ Find the the angle between the direction of the resultant vector A$+$B and the direction of the vector A$.$

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1a To find how far apart the two airplanes are after 33 hours we can use the formula for distance tr... View the full answer