Question: 1) Answer: 0.292866 Explanation: The sample size = 200 reservations x = 182 seats Probability of a passenger with reservation not showing up for the

1)

Answer: 0.292866

Explanation:

The sample size = 200 reservations

x = 182 seats

Probability of a passenger with reservation not showing up for the flight = 0.0995

Probability of a passenger with reservation showing up for the flight = 1- 0.0995 = 0.9005

p(x182) = 1 - 0.707134 = 0.292866

Thus, the probability that when 200 reservations are accepted for United flight 15, there are more passengers that seats available is 0.292866

QUESTION: where did you get the number 0.707134 for calculating p(x182)?

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