1.At an alpha level of .01, test the null hypothesis against the alternative that the mean weight of this sample is no different from the average population weight (). (5 points)

Step 1: Ho: _=191_

Ha: _191_

Step 2: Alpha level = _.01_

Step 3: Sampling distribution is _t sample (t29)_

Step 4: Decision RuleI will reject the Ho if the |_Tobs_| value falls at or beyond

the |Tcrit_| of _-2.76 or 2.76 otherwise I will fail to reject

Step 5: Calculation\_t_obs_/ = (150.90-191)/6.84 = -5.86

Step 6: SummarySince the |_Tobs_| of _-5.86_ falls at or beyond the |_Tcrit_| of _-2.76_, I therefore _reject the Ho_.

Step 7: ConclusionSince _rejection of_ Ho occurred; I conclude that _there is a significant difference_ in mean weight value.

2.Construct appropriate confidence intervals for questions 1 and 2. (5 points)

CI for question 1 = 95% CI = 62.10 63.00 63.90

CI for question 2 = 99% CI = 173.38 191.00 208.621.At an alpha level of .01, test the null hypothesis against the alternative that the mean weight of this sample is no different from the average population weight (). (5 points)

Step 1: Ho: _=191_

Ha: _191_

Step 2: Alpha level = _.01_

Step 3: Sampling distribution is _t sample (t29)_

Step 4: Decision RuleI will reject the Ho if the |_Tobs_| value falls at or beyond

the |Tcrit_| of _-2.76 or 2.76 otherwise I will fail to reject

Step 5: Calculation\_t_obs_/ = (150.90-191)/6.84 = -5.86

Step 6: SummarySince the |_Tobs_| of _-5.86_ falls at or beyond the |_Tcrit_| of _-2.76_, I therefore _reject the Ho_.

Step 7: ConclusionSince _rejection of_ Ho occurred; I conclude that _there is a significant difference_ in mean weight value.

2.Construct appropriate confidence intervals for questions 1 and 2. (5 points)

CI for question 2 = 99% CI = 173.38 191.00 208.62