Question: 1) Based on the series below: an where an = (-1)n+3 n=1 In(In(n + 6) where a n = (1)'1+3 an 1 In(ln(n + 6))

where a n = (1)'1+3 an 1 In(ln(n + 6))

1) Based on the series below:

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an where an = (-1)n+3 n=1 In(In(n + 6)

where a n = (1)'1+3 an 1 In(ln(n + 6))

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