1- Based on the topology, how many subnets are required? *

4

3

2

1

2- How many bits must be borrowed to support the number of subnets in the above logical topology? *

1

2

3

4

3- How many subnets does the borrowed bits create? *

3

4

5

6

4- What subnet mask will be assigned to all devices? *

255.255.255.0

255.255.252.0

255.255.254.0

255.255.255.128

5- How many usable host addresses does this subnetting create in each subnet? *

512

510

520

508

6- What will be the first usable IP address and the broadcast IP address of the 1st subnet? *

First usable IP address: 192.168.160.0 Broadcast IP address: 192.168.160.255

First usable IP address: 192.168.160.255 Broadcast IP address: 192.168.161.255

First usable IP address: 192.168.161.1 Broadcast IP address: 192.168.162.255

First usable IP address: 192.168.160.1 Broadcast IP address: 192.168.161.255

Part 11- Fixed Length Subnet Mask 20 points You have to subnet the network 192.168.160.0/21 into a number of equal size subnets based on the below logical topology. Switch PCO G0/0 G0/1 Switch1 Router GO2 PC1 Switch2 PC2