1. Calculate each subject's weight-relative power for EVERY 5- SECOND INTERVAL; ATTACH YOUR CALCULATIONS TO THE...

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1. Calculate each subject's weight-relative power for EVERY 5- SECOND INTERVAL; ATTACH YOUR CALCULATIONS TO THE BACK OF THE LAB REPORT. Using Microsoft Excel or another.graphing software, graph weight-relative power over time. for each 5-second. interval for each subject. You should use either a line or bar graph to display the results. You may produce one graph with both subjects' data (create a legend to distinguish between subjects). Be sure to label all axes and include units of measurement. Hint: power will be used for the y-axis (left vertical axis) and time will be used for the x-axis (bottom axis). Did the individual with the highest relative power maintain the highest relative power through the whole Wingate? 2. Anaerobic power describes the body's ability to create a maximal rate of work at the expense of ATP and phosphocreatine breakdown; this is usually done during the first 5-10 seconds of maximal work and can be measured by finding the peak power output during the first 10 seconds of the test. Anaerobic capacity can be described as the ability to sustain a high power output for a period of 30-seconds and can be found by finding the average power output (in watts) over the 30-second test. Create a graph that includes each subject's peak anaerobic power and average anaerobic capacity (in watts). Suggestion: create 2 separate graphs. I a. Who had the highest peak anaerobic power? Was this expected? b. Who had the highest anaerobic capacity? Was this expected? c. Does peak anaerobic power influence anaerobic capacity? d. Describe and discuss 2 physiological factors that would have caused a decline in power over the 30 second Wingate test. + Subject 1- weight 179 lbs/81.19/07 x 81.19)=5.68 Subject 2-weight 115 lbs/52.16/05 x 52.16)= 2.61 gender Subject 1 Male Subject 2 Female Force (kg)= Distance (meters) = Work (kgm) 0-5 sec (rev) 13 12 Subject 1 5.68 90 511.2 5-10 sec (rev] 15 14 Peak Power: Power = work/time Subject 16134.4 kgm/min Subject2= 2630.9 kgm/min Subject 2 2.61 84 219.24 10-15 sec (rev) 7 11 15-20 sec (rev) 8 11 Subject 3 20-25 sec (rev) 9 8 Subject 4 25-30 sec (rev) 7 X kgm/min Watts= Relative Power(watts/kg) Subject 1 6134.4 1002.68 12.35 Subject 2 2630.9 430 8.24 Subject 3 Subject 4 1. Calculate each subject's weight-relative power for EVERY 5- SECOND INTERVAL; ATTACH YOUR CALCULATIONS TO THE BACK OF THE LAB REPORT. Using Microsoft Excel or another.graphing software, graph weight-relative power over time. for each 5-second. interval for each subject. You should use either a line or bar graph to display the results. You may produce one graph with both subjects' data (create a legend to distinguish between subjects). Be sure to label all axes and include units of measurement. Hint: power will be used for the y-axis (left vertical axis) and time will be used for the x-axis (bottom axis). Did the individual with the highest relative power maintain the highest relative power through the whole Wingate? 2. Anaerobic power describes the body's ability to create a maximal rate of work at the expense of ATP and phosphocreatine breakdown; this is usually done during the first 5-10 seconds of maximal work and can be measured by finding the peak power output during the first 10 seconds of the test. Anaerobic capacity can be described as the ability to sustain a high power output for a period of 30-seconds and can be found by finding the average power output (in watts) over the 30-second test. Create a graph that includes each subject's peak anaerobic power and average anaerobic capacity (in watts). Suggestion: create 2 separate graphs. I a. Who had the highest peak anaerobic power? Was this expected? b. Who had the highest anaerobic capacity? Was this expected? c. Does peak anaerobic power influence anaerobic capacity? d. Describe and discuss 2 physiological factors that would have caused a decline in power over the 30 second Wingate test. + Subject 1- weight 179 lbs/81.19/07 x 81.19)=5.68 Subject 2-weight 115 lbs/52.16/05 x 52.16)= 2.61 gender Subject 1 Male Subject 2 Female Force (kg)= Distance (meters) = Work (kgm) 0-5 sec (rev) 13 12 Subject 1 5.68 90 511.2 5-10 sec (rev] 15 14 Peak Power: Power = work/time Subject 16134.4 kgm/min Subject2= 2630.9 kgm/min Subject 2 2.61 84 219.24 10-15 sec (rev) 7 11 15-20 sec (rev) 8 11 Subject 3 20-25 sec (rev) 9 8 Subject 4 25-30 sec (rev) 7 X kgm/min Watts= Relative Power(watts/kg) Subject 1 6134.4 1002.68 12.35 Subject 2 2630.9 430 8.24 Subject 3 Subject 4

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1 Calculating WeightRelative Power To calculate weightrelative power for each 5second interval you would need the weight lifted and the time taken for ... View the full answer